The intensity of X-rays from a Coolidge tube | vedclass

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(A) The wavelength of the characteristic $X$-ray line,such as the ${K_\alpha }$ line $({\lambda _k})$,depends only on the material of the target and i

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$({\lambda _K} - {\lambda _C})$ increases

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(A) The wavelength of the characteristic $X$-ray line,such as the ${K_\alpha }$ line $({\lambda _k})$,depends only on the material of the target and is independent of the accelerating voltage $(V)$.The minimum wavelength of the continuous $X$-ray spectrum $({\lambda _c})$ is given by the Duane-Hunt law: ${\lambda _c} = \frac{hc}{eV}$.From this relation,it is clear that ${\lambda _c}$ is inversely proportional to the accelerating voltage $(V)$.As the accelerating voltage $(V)$ is increased,${\lambda _c}$ decreases,while ${\lambda _k}$ remains constant.Therefore,the difference $({\lambda _K} - {\lambda _C})$ will increase.

The intensity of $X$-rays from a Coolidge tube is plotted against wavelength as shown in the figure. The minimum wavelength found is ${\lambda _c}$ and the wavelength of the ${K_\alpha }$ line is ${\lambda _k}$. As the accelerating voltage is increased:

Similar Questions

Find the wavelength of $K_\alpha$ $X$-rays.

An $X$-ray tube operates at $30 \ kV$. What is the minimum wavelength emitted in $\mathring{A}$? (Given: $h = 6.6 \times 10^{-34} \ J \cdot s$,$e = 1.6 \times 10^{-19} \ C$,$c = 3 \times 10^8 \ m/s$)

$X$-rays of wavelength $0.1 \ \mathring A$ are allowed to fall on a metal and get scattered. The wavelength of the scattered radiation is $0.111 \ \mathring A$. If $h = 6.624 \times 10^{-34} \ J \cdot s$ and $m_0 = 9 \times 10^{-31} \ kg$,then the direction of the scattered photons will be:

The $K_{\alpha}$ characteristic $X$-ray refers to the transition:

The power input in an $X$-ray tube is increased by:

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