The interionic distance for $Cesium$ $chloride$ $(CsCl)$ crystal will be (where $a$ is the edge length of the unit cell):

  • A
    $a$
  • B
    $\frac{a}{2}$
  • C
    $\frac{\sqrt{3} a}{2}$
  • D
    $\frac{2a}{\sqrt{3}}$

Explore More

Similar Questions

If the length of the body diagonal of a cube is $x$,then the tetrahedral void will be at a distance of ....... from the center of the cube.

In an $fcc$ crystal lattice,atoms $A$ are present at the corners and atoms $B$ are present at the face centers. If one atom $A$ is missing from a corner,what is the molecular formula of the compound?

What is the total number of adjacent unit cells shared by each face particle of an $fcc$ unit cell?

$Xe$ crystallizes in an $fcc$ structure. If the edge length of the unit cell of $Xe$ is $620 \, pm$, then the distance between two nearest $Xe$ atoms is .............. $pm$.

What is the coordination number of a particle in $fcc$ structure?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo