The intermediate X,in the reaction shown belo | vedclass

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(C) The reaction shown is the Reimer-Tiemann reaction,which involves the treatment of phenol with chloroform $(CHCl_3)$ in the presence of an aqueous

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Sodium $2-$dichloromethylphenoxide

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(C) The reaction shown is the Reimer-Tiemann reaction,which involves the treatment of phenol with chloroform $(CHCl_3)$ in the presence of an aqueous base $(NaOH)$.$1$. The base deprotonates the phenol to form a phenoxide ion.$2$. The chloroform reacts with the base to generate the electrophile,dichlorocarbene $(:CCl_2)$.$3$. The phenoxide ion attacks the dichlorocarbene to form an intermediate,which is sodium $2$-dichloromethylphenoxide.$4$. This intermediate is then hydrolyzed to form salicylaldehyde.Therefore,the intermediate $X$ is sodium $2$-dichloromethylphenoxide.

The intermediate $X$,in the reaction shown below,is ..... .

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