The ionic radii of O^{2-}, F^{-}, Na^{+},and | vedclass

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Question

(D) $Parameter$$O^{2-}, F^{-}, Na^{+}, Mg^{2+}$$Z$ (Atomic number)$8, 9, 11, 12$$e^{-}$ (Electrons)$10, 10, 10, 10$These ions are isoelectronic specie

Vedclass · Accepted Answer

$O^{2-} > F^{-} > Na^{+} > Mg^{2+}$

Vedclass · Answer

(D) $Parameter$$O^{2-}, F^{-}, Na^{+}, Mg^{2+}$$Z$ (Atomic number)$8, 9, 11, 12$$e^{-}$ (Electrons)$10, 10, 10, 10$These ions are isoelectronic species,meaning they all have the same number of electrons $(10)$.For isoelectronic species,the ionic radius decreases as the nuclear charge $(Z)$ increases.As the atomic number $(Z)$ increases,the force of attraction between the nucleus and the electrons increases,causing the ionic size to decrease.The order of atomic numbers is $O (8) Therefore,the order of ionic radii is $O^{2-} > F^{-} > Na^{+} > Mg^{2+}$.Thus,the correct option is $(D)$.

Ion	Radius $(pm)$
$Q^{a+}$	$53$
$X^{b+}$	$66$
$Y^{c+}$	$40$
$Z^{d+}$	$100$

The ionic radii of $O^{2-}, F^{-}, Na^{+}$,and $Mg^{2+}$ are in the order :

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