The ionic radius of Cr is minimum in which of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The oxidation state of $Cr$ in the given compounds is calculated as follows:$1. 	ext{ In } CrCl_3, 	ext{ the oxidation state of } Cr 	ext{ is }

Vedclass · Accepted Answer

$K_2CrO_4$

Vedclass · Answer

(A) The oxidation state of $Cr$ in the given compounds is calculated as follows:$1. 	ext{ In } CrCl_3, 	ext{ the oxidation state of } Cr 	ext{ is } +3$.$2. 	ext{ In } CrF_3, 	ext{ the oxidation state of } Cr 	ext{ is } +3$.$3. 	ext{ In } CrO_2, 	ext{ the oxidation state of } Cr 	ext{ is } +4$.$4. 	ext{ In } K_2CrO_4, 	ext{ the oxidation state of } Cr 	ext{ is } +6$.As the ionic radius of an ion decreases with an increase in its positive oxidation state (due to increased effective nuclear charge),the $Cr$ ion with the highest oxidation state will have the minimum ionic radius.Since $Cr$ has the maximum oxidation state of $+6$ in $K_2CrO_4$,it has the minimum ionic radius among the given compounds.

The ionic radius of $Cr$ is minimum in which of the following compounds?

Similar Questions

The smallest cation and the smallest anion are respectively

Which of the following orders is incorrect for ionic size?

What is atomic radius in reality?

On going down a main sub-group in the periodic table (example $Li$ to $Cs$ in $IA$ or $Be$ to $Ra$ in $IIA$),the expected trend of changes in atomic radius is a

The radius of which ion is closest to that of $Li^{+}$ ion?

Vedclass Test Series

Exam Paper Generator

Online Exam Module