(D) The electronic configuration of Nitrogen $(N)$ is $1s^2 2s^2 2p^3$. The electronic configuration of Oxygen $(O)$ is $1s^2 2s^2 2p^4$. Nitrogen has

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The stability of half-filled $p$-subshell

(D) The electronic configuration of Nitrogen $(N)$ is $1s^2 2s^2 2p^3$. The electronic configuration of Oxygen $(O)$ is $1s^2 2s^2 2p^4$. Nitrogen has a half-filled $p$-subshell $(2p^3)$,which provides extra stability to the atom. Due to this extra stability,more energy is required to remove an electron from Nitrogen compared to Oxygen,which has a partially filled $p$-subshell $(2p^4)$.

Class 11 Chemistry Classification of Elements and Periodicity in Properties Ionisation energy

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The ionisation energy of nitrogen is more than oxygen because of $:-$

A
The size of nitrogen atom is smaller
B
More penetrating effect
C
More attraction of electrons by the nucleus
D
The stability of half-filled $p$-subshell

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Chemistry Questions

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Classification of Elements and Periodicity in Properties

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Ionisation energy

The value of ionization energy of noble gases is ......... .

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The correct order of $2^{nd}$ ionisation potential of carbon,nitrogen,oxygen and fluorine is

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Both nitrogen and oxygen have electrons in the $2p$ orbital. In which of these is the electron-electron repulsion greater,and what is its effect?

Medium

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Identify the incorrect match regarding Ionization Potential $(I.P.)$ trends:

$I.P.$ \text{ Trend} Reason

$A$. $N > O$ Half-filled configuration

$B$. $Zr < Hf$ Lanthanide contraction

$C$. $Na > K$ $Z_{eff}$

$D$. $Al < Ga$ Transition contraction

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The first ionization enthalpy of $Na$,$Mg$ and $Si$,respectively,are: $496, 737$ and $786 \ kJ \ mol^{-1}$. The first ionization enthalpy $(kJ \ mol^{-1})$ of $Al$ is

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$I.P.$ \text{ Trend}	Reason
$A$. $N > O$	Half-filled configuration
$B$. $Zr < Hf$	Lanthanide contraction
$C$. $Na > K$	$Z_{eff}$
$D$. $Al < Ga$	Transition contraction

The ionisation energy of nitrogen is more than oxygen because of $:-$

Similar Questions

The value of ionization energy of noble gases is ......... .

The correct order of $2^{nd}$ ionisation potential of carbon,nitrogen,oxygen and fluorine is

Both nitrogen and oxygen have electrons in the $2p$ orbital. In which of these is the electron-electron repulsion greater,and what is its effect?

Identify the incorrect match regarding Ionization Potential $(I.P.)$ trends: $I.P.$ \text{ Trend} Reason $A$. $N > O$ Half-filled configuration $B$. $Zr < Hf$ Lanthanide contraction $C$. $Na > K$ $Z_{eff}$ $D$. $Al < Ga$ Transition contraction

The first ionization enthalpy of $Na$,$Mg$ and $Si$,respectively,are: $496, 737$ and $786 \ kJ \ mol^{-1}$. The first ionization enthalpy $(kJ \ mol^{-1})$ of $Al$ is

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Identify the incorrect match regarding Ionization Potential $(I.P.)$ trends:

$I.P.$ \text{ Trend} Reason

$A$. $N > O$ Half-filled configuration

$B$. $Zr < Hf$ Lanthanide contraction

$C$. $Na > K$ $Z_{eff}$

$D$. $Al < Ga$ Transition contraction