The isotherms of an ideal gas at T_1, T_2, T_ | vedclass

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(D) For an ideal gas,the equation is $PV = nRT$,which can be rearranged as $P = (nRT) 	imes (\frac{1}{V})$.Comparing this with the equation of a stra

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$m_1 > m_2 > m_3$

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(D) For an ideal gas,the equation is $PV = nRT$,which can be rearranged as $P = (nRT) 	imes (\frac{1}{V})$.Comparing this with the equation of a straight line $y = mx + c$,where $y = P$,$x = \frac{1}{V}$,and $c = 0$,the slope $m$ is equal to $nRT$.Since $n$ and $R$ are constants,the slope $m$ is directly proportional to the temperature $T$ $(m \propto T)$.Given the condition $T_1 > T_2 > T_3$,it follows that the slopes must satisfy the order $m_1 > m_2 > m_3$.

The isotherms of an ideal gas at $T_1, T_2, T_3$ along with their slopes $(m)$ are shown in the graph. If $T_1 > T_2 > T_3$,then the correct order of slopes of these isotherms is:

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