The kinetic energy,due to translational motion,of most of the molecules of an ideal gas at absolute temperature $T$ is proportional to:

  • A
    $kT$
  • B
    $k/T$
  • C
    $T/k$
  • D
    $1/kT$

Explore More

Similar Questions

Assuming the expression for the pressure exerted by the gas, it can be shown that pressure is

The average kinetic energy of a monatomic molecule is $0.414 eV$ at temperature : (Use $K_{B} = 1.38 \times 10^{-23} J/K$) (in $K$)

At what temperature in $^\circ C$ is the average molecular kinetic energy of any gas double that of its value at $20^\circ C$?

The average kinetic energy of $H_2$ at $300 \, K$ is $E$. What is the average kinetic energy of $O_2$ at the same temperature?

Two gases $A$ and $B$ are at absolute temperatures $360 \ K$ and $420 \ K$ respectively. The ratio of average kinetic energy of the molecules of gas $B$ to that of gas $A$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo