The kinetic energy of an electron is 4.55 tim | vedclass

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Question

(A) Given: Kinetic Energy $(KE) = 4.55 	imes 10^{-25} \ J$,mass of electron $(m) = 9.1 	imes 10^{-31} \ kg$,Planck's constant $(h) = 6.626 	imes 10

Vedclass · Accepted Answer

$7.25 	imes 10^{-7} \ m$

Vedclass · Answer

(A) Given: Kinetic Energy $(KE) = 4.55 	imes 10^{-25} \ J$,mass of electron $(m) = 9.1 	imes 10^{-31} \ kg$,Planck's constant $(h) = 6.626 	imes 10^{-34} \ J \ s$.Using the formula for kinetic energy: $KE = \frac{1}{2} mv^2$.$4.55 	imes 10^{-25} = \frac{1}{2} 	imes 9.1 	imes 10^{-31} 	imes v^2$.$v^2 = \frac{2 	imes 4.55 	imes 10^{-25}}{9.1 	imes 10^{-31}} = \frac{9.1 	imes 10^{-25}}{9.1 	imes 10^{-31}} = 10^6$.$v = 10^3 \ m \ s^{-1}$.Applying the de Broglie equation: $\lambda = \frac{h}{mv}$.$\lambda = \frac{6.626 	imes 10^{-34}}{9.1 	imes 10^{-31} 	imes 10^3} = \frac{6.626}{9.1} 	imes 10^{-6} \ m \approx 0.728 	imes 10^{-6} \ m = 7.28 	imes 10^{-7} \ m$.

The kinetic energy of an electron is $4.55 \times 10^{-25} \ J$. Find its wavelength.

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