In the given esterification reaction,the labe | vedclass

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Question

(B) In the esterification reaction between a carboxylic acid and an alcohol,the carboxylic acid loses an $OH$ group and the alcohol loses an $H$ atom

Vedclass · Accepted Answer

Methyl benzoate

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(B) In the esterification reaction between a carboxylic acid and an alcohol,the carboxylic acid loses an $OH$ group and the alcohol loses an $H$ atom to form water.Since the alcohol $CH_3-^{18}OH$ contains the labelled oxygen,the oxygen atom in the resulting ester $Ph-CO-^{18}O-CH_3$ will be the labelled $^{18}O$.Therefore,the labelled $^{18}O$ will be found in the methyl benzoate.

In the given esterification reaction,the labelled $^{18}O$ will be found in:

Similar Questions

$HOOC-COOH + HO^{18}CH_2-CH_2^{18}OH \xrightarrow[H^+]{\Delta} (A)$; Product $(A)$ is:

The correct order of boiling point is $:-$

What is the product of the reaction shown below?

What is the major organic product of the following reaction?
(Image of $2-$methyl$-2,3-$dihydrobenzofuran with an $^{18}O$ atom in the ring,reacting with $H_3O^+$)

In the above reaction,the molecular formula of glycerol increases by:

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