Class 11Chemistry8-3.Organic Chemistry : Purification and characterizationChemical analysis of organic compounds
DifficultThe Lassaigne's extract is boiled with dilute $HNO_3$ before testing for halogens because,
- A$AgCN$ is soluble in $HNO_3$
- BSilver halides are soluble in $HNO_3$
- C$Ag_2S$ is soluble in $HNO_3$
- D$Na_2S$ and $NaCN$ are decomposed by $HNO_3$
Explore More
Similar Questions
The gases respectively absorbed by alkaline pyrogallol and oil of cinnamon are:
Match Column $-I$ with Column $-II$.
Column $-I$ Column $-II$ $(A).$ Dumas method $(3).$ Nitrogen gas $(B).$ Kjeldahl's method $(5).$ Ammonium sulphate $(C).$ Carius method $(1).$ $AgNO_3$ $(D).$ Chromatography $(2).$ Silica gel $(E).$ Homolytic fission $(4).$ Free radical
| Column $-I$ | Column $-II$ |
|---|---|
| $(A).$ Dumas method | $(3).$ Nitrogen gas |
| $(B).$ Kjeldahl's method | $(5).$ Ammonium sulphate |
| $(C).$ Carius method | $(1).$ $AgNO_3$ |
| $(D).$ Chromatography | $(2).$ Silica gel |
| $(E).$ Homolytic fission | $(4).$ Free radical |
Easy
View SolutionMatch the organic compounds in column $I$ with the Lassaigne's test results in column $II$ appropriately.
Column $I$ Column $II$ $A$. Aniline $i$. Red colour with $FeCl_3$ $B$. Benzene sulfonic acid $ii$. Violet colour with sodium nitroprusside $C$. Thiourea $iii$. Blue colour with hot and acidic solution of $FeSO_4$
| Column $I$ | Column $II$ |
|---|---|
| $A$. Aniline | $i$. Red colour with $FeCl_3$ |
| $B$. Benzene sulfonic acid | $ii$. Violet colour with sodium nitroprusside |
| $C$. Thiourea | $iii$. Blue colour with hot and acidic solution of $FeSO_4$ |
DifficultJEE MAIN 2015
View SolutionThe organic compound that gives the following qualitative analysis is:
Test Inference $a$. Dil. $HCl$ Insoluble $b$. $NaOH$ solution Soluble $c$. $Br_2/\text{water}$ Decolourization
| Test | Inference |
|---|---|
| $a$. Dil. $HCl$ | Insoluble |
| $b$. $NaOH$ solution | Soluble |
| $c$. $Br_2/\text{water}$ | Decolourization |
DifficultJEE MAIN 2019
View SolutionMatch the List-$I$ with List-$II$:
List-$I$ (Reagent) List-$II$ (Functional Group detected) $A$. Sodium bicarbonate solution $I$. Double bond/unsaturation $B$. Neutral ferric chloride $II$. Carboxylic acid $C$. Ceric ammonium nitrate $III$. Phenolic $-OH$ $D$. Alkaline $KMnO_4$ $IV$. Alcoholic $-OH$
Choose the correct answer from the options given below:
| List-$I$ (Reagent) | List-$II$ (Functional Group detected) |
| $A$. Sodium bicarbonate solution | $I$. Double bond/unsaturation |
| $B$. Neutral ferric chloride | $II$. Carboxylic acid |
| $C$. Ceric ammonium nitrate | $III$. Phenolic $-OH$ |
| $D$. Alkaline $KMnO_4$ | $IV$. Alcoholic $-OH$ |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2025
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo