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(C) First,convert the dimensions of the room into centimeters:Length $= 15\, m\, 17\, cm = 1517\, cm$Breadth $= 9\, m\, 2\, cm = 902\, cm$To find the

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$814$

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(C) First,convert the dimensions of the room into centimeters:Length $= 15\, m\, 17\, cm = 1517\, cm$Breadth $= 9\, m\, 2\, cm = 902\, cm$To find the least number of square tiles,the side of each square tile must be the $H.C.F.$ of the length and breadth of the room.$H.C.F.$ of $1517$ and $902$:$1517 = 41 	imes 37$$902 = 41 	imes 22$Thus,$H.C.F. = 41\, cm$.The side of each square tile is $41\, cm$.The number of tiles required $= \frac{	ext{Area of the ceiling}}{	ext{Area of one tile}} = \frac{1517 	imes 902}{41 	imes 41} = 37 	imes 22 = 814$.

The least number of square tiles required to cover the ceiling of a room $15\, m\, 17\, cm$ long and $9\, m\, 2\, cm$ broad is:

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