The length of DNA double helix in human sperm | vedclass

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(C) The total number of base pairs in a human diploid cell is $6.6 	imes 10^9$ bp.Since a sperm cell is haploid,it contains half the amount of $DNA$,

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$1.1$ m

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(C) The total number of base pairs in a human diploid cell is $6.6 	imes 10^9$ bp.Since a sperm cell is haploid,it contains half the amount of $DNA$,which is $3.3 	imes 10^9$ bp.The distance between two consecutive base pairs is $0.34 \ 	ext{nm}$ or $0.34 	imes 10^{-9} \ 	ext{m}$.The total length of the $DNA$ double helix is calculated as: $	ext{Length} = 	ext{Number of base pairs} 	imes 	ext{Distance between base pairs}$.$	ext{Length} = (3.3 	imes 10^9) 	imes (0.34 	imes 10^{-9} \ 	ext{m}) = 1.122 \ 	ext{m}$.Therefore,the length is approximately $1.1 \ 	ext{m}$.

The length of $DNA$ double helix in human sperm is approximately . . . . . . .

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