The length of a rectangle is increased by 30 | vedclass

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(D) Let the original length be $L$ and the original breadth be $B$. The original perimeter is $P_1 = 2(L + B)$.After the increase,the new length $L' =

Vedclass · Accepted Answer

Data inadequate

Vedclass · Answer

(D) Let the original length be $L$ and the original breadth be $B$. The original perimeter is $P_1 = 2(L + B)$.After the increase,the new length $L' = 1.3L$ and the new breadth $B' = 1.2B$.The new perimeter is $P_2 = 2(1.3L + 1.2B) = 2.6L + 2.4B$.The percentage increase in perimeter is given by $\frac{P_2 - P_1}{P_1} 	imes 100 = \frac{(2.6L + 2.4B) - 2(L + B)}{2(L + B)} 	imes 100$.This simplifies to $\frac{0.6L + 0.4B}{2(L + B)} 	imes 100 = \frac{0.3L + 0.2B}{L + B} 	imes 100$.Since the ratio of $L$ to $B$ is not provided,the exact percentage increase cannot be determined. Therefore,the data is inadequate.

The length of a rectangle is increased by $30 \%$ and the breadth by $20 \%$. Then the perimeter of the rectangle will increase by what percent?

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