The length of the chord of the parabola $x^2 = 4y$ having the equation $x - \sqrt{2}y + 4\sqrt{2} = 0$ is

  • A
    $3\sqrt{2}$
  • B
    $2\sqrt{11}$
  • C
    $8\sqrt{2}$
  • D
    $6\sqrt{3}$

Explore More

Similar Questions

The area of the triangle formed by the lines joining the vertex of the parabola $x^2 = 12y$ to the ends of its latus rectum is .................. $sq. \ unit$.

The shortest distance between the line $y = x$ and the curve $y^2 = x - 2$ is

The coordinates of a point on the parabola $y^2 = 8x$ whose focal distance is $4$ are

Difficult
View Solution

Let $P$ be a point on the parabola $y^2 = 4ax$,where $a > 0$. The normal to the parabola at $P$ meets the $x$-axis at a point $Q$. The area of the triangle $PFQ$,where $F$ is the focus of the parabola,is $120$. If the slope $m$ of the normal and $a$ are both positive integers,then the pair $(a, m)$ is

Match the items given in List-$A$ with those of the items of List-$B$:
List-$A$List-$B$
$(A)$. The vertex of the parabola $y^2+4x-2y+3=0$ is$(I)$. $\left(\frac{5}{4}, 1\right)$
$(B)$. The vertex of the parabola $x^2+8x+12y+4=0$ is$(II)$. $\left(1, \frac{5}{4}\right)$
$(C)$. The focus of the parabola $y^2-x-2y+2=0$ is$(III)$. $\left(-\frac{1}{2}, 1\right)$
$(D)$. The focus of the parabola $x^2-2x-8y-23=0$ is$(IV)$. $(1, -1)$
$(V)$. $(-4, 1)$

The correct match is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo