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(A) The length of the minute hand is the radius of the circle,$r = 14 \, cm$.When the minute hand moves from $1$ to $10$,it covers $9$ divisions out o

Vedclass · Accepted Answer

$462$

Vedclass · Answer

(A) The length of the minute hand is the radius of the circle,$r = 14 \, cm$.When the minute hand moves from $1$ to $10$,it covers $9$ divisions out of $12$ on the clock face.The angle subtended by the minute hand at the center is $	heta = \frac{9}{12} 	imes 360^\circ = \frac{3}{4} 	imes 360^\circ = 270^\circ$.The area covered by the minute hand is the area of the sector with angle $	heta = 270^\circ$.Area of sector $= \frac{	heta}{360^\circ} 	imes \pi r^2$.Area $= \frac{270}{360} 	imes \frac{22}{7} 	imes 14 	imes 14$.Area $= \frac{3}{4} 	imes 22 	imes 2 	imes 14$.Area $= 3 	imes 11 	imes 14 = 462 \, cm^2$.

The length of the minute hand of a clock is $14 \, cm$. If the minute hand moves from $1$ to $10$ on the dial,then $\ldots \ldots \ldots \ldots \, cm^2$ area will be covered.

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