The length of a seconds pendulum on the surface of the Earth is $1\, m$. The length of a seconds pendulum on the surface of the Moon,where $g$ is $1/6$th the value of $g$ on the surface of the Earth,is:

  • A
    $\frac{1}{6}\, m$
  • B
    $6 \,m$
  • C
    $\frac{1}{36}\, m$
  • D
    $36 \,m$

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