The length of the subtangent at (2, 2) to the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the curve equation: $2y^4 = x^5$. On differentiating both sides with respect to $x$,we get: $8y^3 \frac{dy}{dx} = 5x^4$. Thus,the slope of t

Vedclass · Accepted Answer

$8/5$

Vedclass · Answer

(B) Given the curve equation: $2y^4 = x^5$. On differentiating both sides with respect to $x$,we get: $8y^3 \frac{dy}{dx} = 5x^4$. Thus,the slope of the tangent at $(2, 2)$ is: $\left(\frac{dy}{dx}ight)_{(2, 2)} = \frac{5(2)^4}{8(2)^3} = \frac{5 	imes 16}{8 	imes 8} = \frac{80}{64} = \frac{5}{4}$. The formula for the length of the subtangent is given by $\left| \frac{y}{dy/dx} ight|$. Substituting the values,we get: Length of subtangent $= \frac{2}{5/4} = 2 	imes \frac{4}{5} = \frac{8}{5}$.

The length of the subtangent at $(2, 2)$ to the curve $x^5 = 2y^4$ is

Similar Questions

The equation of the normal to the curve $2x^{2} + y^{2} = 12$ at the point $(2, 2)$ is

The equation of the tangent to the curve $6y = 7 - x^3$ at the point $(1, 1)$ is:

The line which is parallel to the $x$-axis and intersects the curve $y = \sqrt{x}$ at an angle of $45^\circ$ is given by:

If the length of the subnormal at any point on the curve $y^n = a^{n-1}x$ is constant,then $n = ......$

The equation of the tangent to the curve $y=\sqrt{9-2x^2}$ at the point where the ordinate and abscissa are equal is

Vedclass Test Series

Exam Paper Generator

Online Exam Module