(A) The frequency $\nu$ is given by the formula $\nu = R_{\infty} \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$.For the Balmer series,$n_1 = 2$ an

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(A) The frequency $\nu$ is given by the formula $\nu = R_{\infty} \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$.For the Balmer series,$n_1 = 2$ and $n_2 = 3, 4, 5, \dots, \infty$.The limiting line corresponds to the transition from $n_2 = \infty$ to $n_1 = 2$.Substituting the values: $\nu = 3.29 \times 10^{15} \left( \frac{1}{2^2} - \frac{1}{\infty^2} \right)$.$\nu = 3.29 \times 10^{15} \times \frac{1}{4} = 8.225 \times 10^{14} \ s^{-1}$.

Class 11 Chemistry Structure of Atom Atomic models and Planck's quantum theory

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The limiting line in the Balmer series will have a frequency of (Rydberg constant,$R_{\infty} = 3.29 \times 10^{15} \ s^{-1}$)

AIEEE 2012 All AIEEE

A
$8.22 \times 10^{14} \ s^{-1}$
B
$3.29 \times 10^{15} \ s^{-1}$
C
$3.65 \times 10^{14} \ s^{-1}$
D
$5.26 \times 10^{13} \ s^{-1}$

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Structure of Atom

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Atomic models and Planck's quantum theory

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The limiting line in the Balmer series will have a frequency of (Rydberg constant,$R_{\infty} = 3.29 \times 10^{15} \ s^{-1}$)

Similar Questions

An electron in a hydrogen atom in its ground state absorbs $2$ times as much energy as the minimum required for it to escape from the atom. The kinetic energy of the emitted electron is ............ $eV$.

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