The line,that is coplanar to the line $\frac{x+3}{-3}=\frac{y-1}{1}=\frac{z-5}{5}$,is

  • A
    $\frac{x+1}{1}=\frac{y-2}{2}=\frac{z-5}{5}$
  • B
    $\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}$
  • C
    $\frac{x+1}{-1}=\frac{y-2}{2}=\frac{z-5}{4}$
  • D
    $\frac{x-1}{-1}=\frac{y-2}{2}=\frac{z-5}{5}$

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