The load versus elongation graph for four wir | vedclass

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(C) The formula for elongation $\Delta x$ in a wire is given by $\Delta x = \frac{FL}{AY}$,where $F$ is the load,$L$ is the length,$A$ is the cross-se

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$OA$

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(C) The formula for elongation $\Delta x$ in a wire is given by $\Delta x = \frac{FL}{AY}$,where $F$ is the load,$L$ is the length,$A$ is the cross-sectional area,and $Y$ is the Young's modulus.Since all wires have the same length $L$ and are made of the same material (same $Y$),for a constant load $F$,we have $\Delta x \propto \frac{1}{A}$.This means that for a given load,the wire with the maximum elongation will have the minimum cross-sectional area,making it the thinnest wire.Looking at the graph,for a fixed load,the elongation is maximum for line $OA$.Therefore,$OA$ represents the thinnest wire.

The load versus elongation graph for four wires of same length and the same material is shown in the figure. The thinnest wire is represented by the line:

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