The logical equivalent of $p \Leftrightarrow q$ is :-
- A$(p \wedge q) \vee (\neg p \wedge \neg q)$
- B$(p$ $\Rightarrow q) \wedge (q$ $\Rightarrow p)$
- C$(p \wedge q) \vee (q \Rightarrow p)$
- D$(p \wedge q) \Rightarrow (q \vee p)$
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Easy
View SolutionThe statement pattern $[(p \land q) \to (\sim p \lor r)] \lor [(\sim p \lor r) \to (p \land q)]$ is
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