The lower stability of ethyl anion compared t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The lower stability of ethyl anion $(CH_3CH_2^-)$ compared to methyl anion $(CH_3^-)$ is due to the $+I$-effect of the methyl group,which increase

Vedclass · Accepted Answer

$+I$-effect of the methyl group in ethyl anion; $\sigma \rightarrow p$-orbital conjugation in ethyl radical

Vedclass · Answer

(A) The lower stability of ethyl anion $(CH_3CH_2^-)$ compared to methyl anion $(CH_3^-)$ is due to the $+I$-effect of the methyl group,which increases the electron density on the already negatively charged carbon atom,thereby destabilizing it.The higher stability of the ethyl radical $(CH_3CH_2^\bullet)$ compared to the methyl radical $(CH_3^\bullet)$ is due to $\sigma \rightarrow p$-orbital conjugation,which is known as hyperconjugation. This delocalization of electrons from the $\sigma$-bond of the $C-H$ bond into the half-filled $p$-orbital stabilizes the radical.

The lower stability of ethyl anion compared to methyl anion and the higher stability of ethyl radical compared to methyl radical,respectively,are due to

Similar Questions

Which one of the following is the most stable carbocation?

For the following radicals,the correct order of their stability is

Identify the most stable carbocation from the following:

List the following carbocations in order of decreasing stability.

The decreasing order of stability of the given carbocations is

Vedclass Test Series

Exam Paper Generator

Online Exam Module