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(D) When a force is applied at an angle of $30^{\circ}$ to the surface of a cube,it can be resolved into two rectangular components.$1$. The component

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Shape and size

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(D) When a force is applied at an angle of $30^{\circ}$ to the surface of a cube,it can be resolved into two rectangular components.$1$. The component parallel to the surface $(F \cos 30^{\circ})$ causes shear stress,which results in a change in the shape of the cube.$2$. The component perpendicular to the surface $(F \sin 30^{\circ})$ causes normal stress (compressive or tensile),which results in a change in the size (volume) of the cube.Therefore,the applied force produces both shear and normal stresses,leading to a change in both the shape and the size of the cube.

The lower surface of a cube is fixed. On its upper surface,a force is applied at an angle of $30^{\circ}$ from its surface. The change will be of the type:

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