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(C) The magnetic field at the centre of a circular current loop is given by $B = \frac{\mu_0 I}{2r}$.The current $I$ produced by an electron revolving

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$B/32$

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(C) The magnetic field at the centre of a circular current loop is given by $B = \frac{\mu_0 I}{2r}$.The current $I$ produced by an electron revolving in an orbit is $I = \frac{e}{T} = ef$,where $f$ is the frequency of revolution.According to Bohr's theory,the frequency $f \propto \frac{1}{n^3}$ and the radius $r \propto n^2$.Substituting these into the expression for $B$:$B \propto \frac{f}{r} \propto \frac{1/n^3}{n^2} = \frac{1}{n^5}$.For the first orbit $(n_1 = 1)$,$B_1 = B$.For the second orbit $(n_2 = 2)$,$B_2 = B_1 	imes (n_1/n_2)^5 = B 	imes (1/2)^5 = B/32$.

The magnetic field at the centre due to the motion of an electron in the first Bohr orbit is $B$. The magnetic field due to the motion of an electron in the second Bohr orbit at the centre will be

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