The magnetic field induction at the centre of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic field induction $B$ at the centre of a circular coil is given by the formula:$B = \frac{\mu_0 I}{2r} \quad \dots(i)$We know the relat

Vedclass · Accepted Answer

$\frac{1}{\varepsilon_0 10^{16}}$

Vedclass · Answer

(A) The magnetic field induction $B$ at the centre of a circular coil is given by the formula:$B = \frac{\mu_0 I}{2r} \quad \dots(i)$We know the relationship between the speed of light $c$, permeability $\mu_0$, and permittivity $\varepsilon_0$ as:$c^2 = \frac{1}{\mu_0 \varepsilon_0} \implies \mu_0 = \frac{1}{\varepsilon_0 c^2}$Substituting this into equation $(i)$:$B = \left( \frac{1}{\varepsilon_0 c^2} ight) \frac{I}{2r}$Given values: $I = 0.9 \,A$, $r = 5 \,cm = 5 	imes 10^{-2} \,m$, $c = 3 	imes 10^8 \,ms^{-1}$.$B = \frac{1}{\varepsilon_0 (3 	imes 10^8)^2} 	imes \frac{0.9}{2 	imes 5 	imes 10^{-2}}$$B = \frac{1}{\varepsilon_0 	imes 9 	imes 10^{16}} 	imes \frac{0.9}{10 	imes 10^{-2}}$$B = \frac{1}{\varepsilon_0 	imes 9 	imes 10^{16}} 	imes \frac{0.9}{0.1} = \frac{1}{\varepsilon_0 	imes 9 	imes 10^{16}} 	imes 9$$B = \frac{1}{\varepsilon_0 	imes 10^{16}}$

The magnetic field induction at the centre of a circular coil of radius $5 \,cm$ carrying a current of $0.9 \,A$ is (in $SI$ units) (where $\varepsilon_0$ is the absolute permittivity of air in $SI$ units, and the velocity of light $c = 3 \times 10^8 \,ms^{-1}$):

Similar Questions

In the figure,two parallel infinitely long current-carrying wires are shown. If the resultant magnetic field at point $A$ is zero,then determine the current $I$ (in $A$).

The electric current in a circular coil of four turns produces a magnetic induction $32 \ T$ at its centre. The coil is unwound and is rewound into a circular coil of a single turn. If the same current flows through the new coil,the magnetic induction at the centre will be $.......... \ T$.

In the following figure,the magnitude of the magnetic field at the point $P$ is:

The figure shows two semicircular loops of radii $R_1$ and $R_2$ carrying current $I$. The magnetic field at the common centre '$O$' is

$A$ current $i$ is flowing in a straight conductor of length $L.$ The magnetic induction at a point on its axis at a distance $\frac{L}{4}$ from its centre will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module