Class 12PhysicsMoving Charges and MagnetismAmpere’s circuital law and its application (Solenoid and Toroid)
EasyThe magnetic field intensity inside a current-carrying solenoid is $H = 2.4 \times 10^3 \ A/m$. If the length and the number of turns of the solenoid are $15 \ cm$ and $60$ turns respectively,the current flowing in the solenoid is: (in $A$)
- A$4$
- B$6$
- C$0.6$
- D$60$
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$A$ solenoid of length $80 \, cm$ and radius $3 \, cm$ produces a magnetic field of $B = 0.2 \, T$ when a current of $10 \, A$ is passed through it. What is the total length of the wire used in the solenoid?
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