The magnetic flux through a coil perpendicula | vedclass

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(A) The magnetic flux is given by $\phi = 5t^3 + 4t^2 + 2t - 5$. According to Faraday's law of induction,the magnitude of the induced electromotive fo

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$15$

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(A) The magnetic flux is given by $\phi = 5t^3 + 4t^2 + 2t - 5$. According to Faraday's law of induction,the magnitude of the induced electromotive force $(EMF)$ is given by $|e| = |\frac{d\phi}{dt}|$. Differentiating $\phi$ with respect to $t$: $|e| = \frac{d}{dt}(5t^3 + 4t^2 + 2t - 5) = 15t^2 + 8t + 2$. At $t = 2 \; s$,the induced $EMF$ is: $|e| = 15(2)^2 + 8(2) + 2 = 15(4) + 16 + 2 = 60 + 16 + 2 = 78 \; V$. The induced current $I$ is given by $I = \frac{|e|}{R}$,where $R = 5 \; \Omega$. $I = \frac{78}{5} = 15.6 \; A$.

The magnetic flux through a coil perpendicular to its plane is varying according to the relation $\phi = (5t^3 + 4t^2 + 2t - 5) \; Wb$. If the resistance of the coil is $5 \; \Omega$,then the induced current through the coil at $t = 2 \; s$ will be $.... \; A$. (in $.6$)

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