The magnetic moment of a magnet of length $10\, cm$ and pole strength $4.0\, Am$ will be......$A\,m^2$.

$A$ wire of magnetic moment $M$ is bent to form a circular arc which subtends an angle $90^o$ at the center. Then,its new magnetic moment is:

Two identical thin bar magnets,each of length $l$ and pole strength $m$,are placed at a right angle to each other with the north pole of one touching the south pole of the other. The magnetic moment of the system is

$A$ sample of a ferromagnetic iron in the shape of a cube of side $1.0 \mu m$ contains $8.7 \times 10^{28}$ atoms per cubic metre and the magnetic dipole moment of each iron atom is $9.3 \times 10^{-24} A m^2$. Then the maximum possible magnetic dipole moment (in $A m^2$) of the sample is nearly

What is the fundamental difference between an electric dipole and a magnetic dipole?

$A$ steel wire of length $\ell$ has a magnetic moment $M$. It is then bent into a semicircular arc. The new magnetic moment is