The magnifying power of a telescope is 9. Whe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnifying power of a telescope adjusted for parallel rays (normal adjustment) is given by $m = \frac{f_o}{f_e} = 9$,where $f_o$ is the focal

Vedclass · Accepted Answer

$18\; cm$ and $2\; cm$

Vedclass · Answer

(C) The magnifying power of a telescope adjusted for parallel rays (normal adjustment) is given by $m = \frac{f_o}{f_e} = 9$,where $f_o$ is the focal length of the objective and $f_e$ is the focal length of the eyepiece. From this,we get $f_o = 9f_e$ ..... $(i)$The length of the telescope tube in normal adjustment is the sum of the focal lengths of the objective and eyepiece: $L = f_o + f_e = 20\; cm$ ..... $(ii)$Substituting equation $(i)$ into equation $(ii)$:$9f_e + f_e = 20\; cm$$10f_e = 20\; cm$$f_e = 2\; cm$Now,substituting $f_e = 2\; cm$ back into equation $(i)$:$f_o = 9 	imes 2\; cm = 18\; cm$Thus,the focal lengths are $18\; cm$ and $2\; cm$.

The magnifying power of a telescope is $9.$ When it is adjusted for parallel rays,the distance between the objective and eyepiece is $20\; cm.$ The focal lengths of the lenses are:

Similar Questions

Consider a refracting telescope whose objective has a focal length of $1 \ m$ and the eyepiece has a focal length of $1 \ cm$. The magnifying power of this telescope will be . . . . . . .

All of the following statements are correct except:

For a distant object,the angular magnification of an astronomical telescope is $5$. The distance between the objective and the eyepiece is $36 \, cm$,and the final image is formed at infinity. What are the focal lengths of the objective $(f_o)$ and the eyepiece $(f_e)$?

Focal length of objective and eye piece of telescope are $200 \; cm$ and $4 \; cm$ respectively. What is the length of telescope for normal adjustment (in $; cm$)?

In a Galilean telescope,if the powers of an objective and eye lens are respectively $+1.25 \, D$ and $-20 \, D$,then for relaxed vision,the length and magnification will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module