The magnitude of surface tension of a liquid | vedclass

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(A) The magnitude of surface tension is directly proportional to the strength of intermolecular attractive forces.$1$. Hexane $(CH_3(CH_2)_4CH_3)$ is

Vedclass · Accepted Answer

Hexane < Alcohol < Water

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(A) The magnitude of surface tension is directly proportional to the strength of intermolecular attractive forces.$1$. Hexane $(CH_3(CH_2)_4CH_3)$ is a non-polar molecule,exhibiting only weak London dispersion forces.$2$. Alcohol $(C_2H_5OH)$ is a polar molecule capable of $H$-bonding,which is stronger than dispersion forces.$3$. Water $(H_2O)$ is a highly polar molecule with extensive $H$-bonding,making its intermolecular forces the strongest among the three.Therefore,the increasing order of surface tension is $Hexane < Alcohol < Water$.

The magnitude of surface tension of a liquid depends on the attractive forces between the molecules. Arrange the following in increasing order of surface tension: Water,alcohol $(C_2H_5OH)$,and hexane $(CH_3(CH_2)_4CH_3)$.

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