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(C) The reaction sequence is as follows:$1$. Phenol reacts with $CO_2$ in the presence of $NaOH$ followed by acidification $(H^+)$,which is the Kolbe-

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(C) The reaction sequence is as follows:$1$. Phenol reacts with $CO_2$ in the presence of $NaOH$ followed by acidification $(H^+)$,which is the Kolbe-Schmitt reaction. This yields salicylic acid ($2$-hydroxybenzoic acid) as intermediate $A$.$2$. Salicylic acid then reacts with acetic anhydride $(CH_3CO)_2O$ (acetylation of the phenolic -$OH$ group) to form acetylsalicylic acid,commonly known as Aspirin.

The main product of the following reaction will be:

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