The major product 'P' formed in the given rea | vedclass

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(C) The reaction involves the oxidation of side chains on a naphthalene ring using alkaline $KMnO_4$ followed by acidic workup.$1$. The ethyl group $(

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(C) The reaction involves the oxidation of side chains on a naphthalene ring using alkaline $KMnO_4$ followed by acidic workup.$1$. The ethyl group $(-CH_2CH_3)$ at the benzylic position has $\alpha$-hydrogens,so it is oxidized to a carboxylic acid group $(-COOH)$.$2$. The vinyl group $(-CH=CH_2)$ is also oxidized to a carboxylic acid group $(-COOH)$ by strong oxidizing agents like alkaline $KMnO_4$.$3$. The ester group $(-COOCH_3)$ is hydrolyzed under alkaline conditions to a carboxylate salt,which upon acidic workup $(H_3O^+)$ becomes a carboxylic acid group $(-COOH)$.$4$. Therefore,all three side chains are converted into carboxylic acid groups,resulting in the product shown in option $C$.

The major product '$P$' formed in the given reaction is

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