The major product (P) formed in the reaction | vedclass

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(A) The reaction involves the electrophilic addition of $Br_2$ to an alkene in the presence of $CCl_4$ at low temperature $(253 \ K)$.Alkenes are more

Vedclass · Accepted Answer

$HC \equiv C-CH_2-CH(Br)-CH_2Br$

Vedclass · Answer

(A) The reaction involves the electrophilic addition of $Br_2$ to an alkene in the presence of $CCl_4$ at low temperature $(253 \ K)$.Alkenes are more reactive towards electrophilic addition than alkynes.Therefore,$Br_2$ selectively adds across the double bond to form a vicinal dibromide.The reaction is: $HC \equiv C-CH_2-CH=CH_2 + Br_2 \xrightarrow{CCl_4} HC \equiv C-CH_2-CH(Br)-CH_2Br$.Thus,the major product is $HC \equiv C-CH_2-CH(Br)-CH_2Br$.

The major product $(P)$ formed in the reaction below is: $HC \equiv C-CH_2-CH=CH_2 \xrightarrow[CCl_4, 253 \ K]{Br_2(1 \ mol)} P$

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