The major product formed by the reaction of benzylamine with nitrous acid is

The correct statements of the following are:
$A$. Aniline forms a stable benzene diazonium chloride at $285 \ K$.
$B$. $N$-Phenylethanamide is less reactive towards nitration than aniline.
$C$. $p-CH_3C_6H_4COCl$ is Hinsberg reagent.

Boiling ethylamine on reaction with acidified $KMnO_4$ gives:

Which of the following is the most basic compound?

$A$ reaction of $0.1 \ mol$ of Benzylamine with bromomethane gave $23 \ g$ of Benzyl trimethyl ammonium bromide. The number of moles of bromomethane consumed in this reaction are $n \times 10^{-1},$ when $n = \dots$ (Round off to the Nearest Integer).
(Given : Atomic masses: $C : 12.0 \ u, H : 1.0 \ u, N : 14.0 \ u, Br : 80.0 \ u$)

Consider the reaction sequence from $P$ to $Q$ shown below. The overall yield of the major product $Q$ from $P$ is $75 \%$. What is the amount in grams of $Q$ obtained from $9.3 \ mL$ of $P$? (Use density of $P = 1.00 \ g \ mL^{-1}$,Molar mass of $C = 12.0, H = 1.0, O = 16.0$ and $N = 14.0 \ g \ mol^{-1}$)