The major product formed in the following rea | vedclass

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(A) The reaction sequence is as follows:$1$. The reaction of phenol with $NaOH$ followed by $CO_2$ and then $H^+/H_2O$ is the Kolbe-Schmitt reaction,w

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Aspirin (o-acetoxybenzoic acid)

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(A) The reaction sequence is as follows:$1$. The reaction of phenol with $NaOH$ followed by $CO_2$ and then $H^+/H_2O$ is the Kolbe-Schmitt reaction,which yields salicylic acid ($2$-hydroxybenzoic acid).$2$. The subsequent reaction with $CH_3COCl$ in the presence of pyridine is an acetylation reaction of the phenolic $-OH$ group.$3$. This converts the $-OH$ group of salicylic acid into an acetoxy group $(-OCOCH_3)$,resulting in the formation of aspirin ($2$-acetoxybenzoic acid).

The major product formed in the following reaction is:

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