The major product in Reimer-Tiemann reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The Reimer-Tiemann reaction involves the treatment of phenol with chloroform $(CHCl_3)$ in the presence of an aqueous base like sodium hydroxide $

Vedclass · Accepted Answer

Salicylaldehyde,$CHCl_3$,$Aq. NaOH$

Vedclass · Answer

(A) The Reimer-Tiemann reaction involves the treatment of phenol with chloroform $(CHCl_3)$ in the presence of an aqueous base like sodium hydroxide $(NaOH)$.This reaction results in the introduction of a formyl group $(-CHO)$ at the ortho position of the phenol ring,yielding salicylaldehyde (o-hydroxybenzaldehyde) as the major product.Therefore,$X$ is salicylaldehyde,$Y$ is $CHCl_3$,and $Z$ is $Aq. NaOH$.

The major product in Reimer-Tiemann reaction is $X$. The reactants are $Y$ and $Z$. $X$,$Y$ and $Z$ are respectively.

Similar Questions

What are $A$,$B$ and $C$ in the following reactions?
$\text{Cumene}$ $\xrightarrow{O_2} A$ $\xrightarrow{H_3O^{+}} B + C$

Explain why the $-OH$ group in phenols is more strongly held as compared to the $-OH$ group in alcohols?

The major products of the following reaction are:

Which of the following compounds is the most acidic?

Which of the following is pyrogallol?

Vedclass Test Series

Exam Paper Generator

Online Exam Module