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(B) The reaction involves two steps when $HBr$ is in excess and heat is applied:$1$. The ether group $(-OCH_3)$ undergoes cleavage by $HBr$ to form a

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(B) The reaction involves two steps when $HBr$ is in excess and heat is applied:$1$. The ether group $(-OCH_3)$ undergoes cleavage by $HBr$ to form a phenol $(-OH)$ and methyl bromide $(CH_3Br)$.$2$. The alkene group $(-CH=CH-CH_3)$ undergoes electrophilic addition of $HBr$ following Markownikoff's rule.According to Markownikoff's rule,the electrophile $H^+$ adds to the carbon with more hydrogens,and the nucleophile $Br^-$ adds to the more substituted carbon,resulting in the formation of a stable carbocation intermediate. Thus,the product is $4-(1-bromopropyl)phenol$.

The major product in the following conversion is

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