The major product obtained by the dehydration | vedclass

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(A) The dehydration of alcohol in the presence of $H_3PO_4$ and heat proceeds via an $E1$ mechanism involving the formation of a carbocation intermedi

Vedclass · Accepted Answer

$1-$phenyl$-3-$methylcyclohex$-1-$ene

Vedclass · Answer

(A) The dehydration of alcohol in the presence of $H_3PO_4$ and heat proceeds via an $E1$ mechanism involving the formation of a carbocation intermediate. $1$. Protonation of the $-OH$ group occurs,followed by the loss of a water molecule to form a secondary carbocation at the $C_2$ position. $2$. The carbocation is adjacent to a phenyl group $(Ph)$ at $C_1$,which provides resonance stabilization. $3$. Elimination of a proton $(H^+)$ can occur from either $C_1$ or $C_3$. $4$. Elimination from $C_1$ leads to a double bond between $C_1$ and $C_2$,which is conjugated with the phenyl ring. This forms the most stable product,$1$-phenyl$-3-$methylcyclohex$-1-$ene. Thus,the major product is $1-$phenyl$-3-$methylcyclohex$-1-$ene.

The major product obtained by the dehydration of the given alcohol is $:-$

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