The major product obtained in the following reaction is $C_2H_5ONa + (CH_3)_3C-Cl \rightarrow$

Which one of the following compounds is inactive towards $S_N1$ reaction?

In the given pairs of reactions,in which pair is the second reaction more reactive than the first toward $S_{N}2$ reaction?

Which among the following compounds will undergo the fastest $S_{N}2$ reaction?

Consider the following four reactions: $(I) C_6H_5-CHCl-CH_3 \xrightarrow{95\% \text{ acetone}, 5\% \text{ water}} C_6H_5-CH(OH)-CH_3$ $(II) C_6H_5-CHCl-CH_3 \xrightarrow{90\% \text{ acetone}, 10\% \text{ water}} C_6H_5-CH(OH)-CH_3$ $(III) C_6H_5-CHCl-CH_3 \xrightarrow{80\% \text{ acetone}, 20\% \text{ water}} C_6H_5-CH(OH)-CH_3$ $(IV) C_6H_5-CHCl-CH_3 \xrightarrow{100\% \text{ water}} C_6H_5-CH(OH)-CH_3$ Arrange these reactions in decreasing order of the proportion of inverted product and select the correct answer from the codes given below:

The order of the rate of $S_N1$ reactivity for the following compounds is: