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(A) The reaction of aniline $(C_6H_5NH_2)$ with acetic anhydride $(CH_3CO)_2O$ is an acetylation reaction. In this reaction,the lone pair of electrons

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(A) The reaction of aniline $(C_6H_5NH_2)$ with acetic anhydride $(CH_3CO)_2O$ is an acetylation reaction. In this reaction,the lone pair of electrons on the nitrogen atom of the aniline attacks the carbonyl carbon of the acetic anhydride. This leads to the formation of $N$-phenylethanamide,commonly known as acetanilide $(C_6H_5NHCOCH_3)$,and acetic acid $(CH_3COOH)$ as a byproduct. The reaction is: $C_6H_5NH_2 + (CH_3CO)_2O \rightarrow C_6H_5NHCOCH_3 + CH_3COOH$ Therefore,the major product is $N$-phenylethanamide.

The major product obtained in the reaction of aniline with acetic anhydride is

Similar Questions

Identify the product $A$ in the following reaction:
$[(CH_3CH_2CH_2)(CH_3CH_2)_3N]^+ OH^- \xrightarrow{\Delta, -H_2O} A + (CH_3CH_2CH_2)(CH_3CH_2)_2N$

$C_6H_5NH_2 \xrightarrow{Br_2/CCl_4} ?$
What is the product?

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Which of the following compounds reacts with acetone to form a product containing the $>C = N -$ group?

The product $(C)$ in the above reaction is:

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