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(B) The reaction involves the electrophilic addition of benzene to the alkene $CH_3-CH(NO_2)-CH=CH_2$ in the presence of an acid catalyst $(H_2SO_4)$.

Vedclass · Accepted Answer

$2-$nitro$-3-$phenylbutane

Vedclass · Answer

(B) The reaction involves the electrophilic addition of benzene to the alkene $CH_3-CH(NO_2)-CH=CH_2$ in the presence of an acid catalyst $(H_2SO_4)$.$1$. The acid protonates the alkene to form a carbocation intermediate.$2$. The most stable carbocation is formed,which is the secondary carbocation at the carbon adjacent to the $NO_2$ group due to resonance stabilization or inductive effects.$3$. Benzene acts as a nucleophile and attacks the carbocation to form the final product,which is $2-nitro-3-phenylbutane$.

The major product of the following reaction is:

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