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Question

(B) The reaction of $1$-methylcyclohex-$1$-ene with $Br_2$ in the presence of light $(h
u)$ is a free radical substitution reaction (allylic brominat

Vedclass · Accepted Answer

$1-$bromo$-1-$methylcyclohex$-2-$ene

Vedclass · Answer

(B) The reaction of $1$-methylcyclohex-$1$-ene with $Br_2$ in the presence of light $(h
u)$ is a free radical substitution reaction (allylic bromination).In this reaction,the bromine radical $(Br^\bullet)$ abstracts a hydrogen atom from the allylic position.The most stable free radical formed is the tertiary $(3^\circ)$ allylic radical at the $C-1$ position.This radical then reacts with $Br_2$ to form $1$-bromo-$1$-methylcyclohex-$2$-ene as the major product.

The major product of the following reaction is

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