The major product of the following reaction is:

  • A
    $6-$bromo$-1-$indanone
  • B
    $4-$bromo$-1-$indanone
  • C
    $4-$hydroxy$-1-$indanone
  • D
    $6-$hydroxy$-1-$indanone

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Consider the following sequence of reactions:
$2\text{-benzylbenzoic acid}$ $\xrightarrow{SOCl_2} A$ $\xrightarrow[2. H_3O^+]{1. AlCl_3} B$ $\xrightarrow{Zn-Hg, \text{conc. } HCl, \text{heat}} C$
The end product $(C)$ is:

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$CH_3CO_2C_2H_5$ on reaction with sodium ethoxide in ethanol gives $A$,which on heating in the presence of acid gives $B$. Compound $B$ is

$G$ in the above sequence of reactions is

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