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(A) The reaction involves the nitration of $2$-methyl$-4-$nitrophenol using concentrated $HNO_3$ and concentrated $H_2SO_4$. The $-OH$ group is a stro

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$2-$methyl$-4,6-$dinitrophenol

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(A) The reaction involves the nitration of $2$-methyl$-4-$nitrophenol using concentrated $HNO_3$ and concentrated $H_2SO_4$. The $-OH$ group is a strong activating group and is ortho/para directing. The $-CH_3$ group is also ortho/para directing. The $-NO_2$ group is meta directing. In $2$-methyl$-4-$nitrophenol,the positions ortho to the $-OH$ group are position $6$ (which is vacant) and position $3$ (which is also vacant). However,position $6$ is less sterically hindered compared to position $3$,which is adjacent to the $-CH_3$ group. Therefore,the incoming $-NO_2^+$ electrophile attacks the $6$-position to form $2$-methyl$-4,6-$dinitrophenol as the major product.

The major product of the following reaction is:

Similar Questions

Regarding the solubility of $p$-nitrophenol and salicylaldehyde in a base:

The major product of the following reaction is:

Which of the following substances is the most volatile?

$4.7 \text{ g}$ of phenol is heated with $Zn$ to give product $X$. If this reaction goes to $60\%$ completion, then the number of moles of compound $X$ formed will be . . . . . . $\times 10^{-2}$. (Nearest Integer) (Given molar mass in $\text{g mol}^{-1}$: $H:1, C:12, O:16$)

The following reaction is known as:
$Phenol \xrightarrow[H^{+}]{CHCl_3 / NaOH} \text{Salicylaldehyde}$

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The major product of the following reaction is:

Similar Questions

Regarding the solubility of $p$-nitrophenol and salicylaldehyde in a base:

The major product of the following reaction is:

Which of the following substances is the most volatile?

$4.7 \text{ g}$ of phenol is heated with $Zn$ to give product $X$. If this reaction goes to $60\%$ completion, then the number of moles of compound $X$ formed will be . . . . . . $\times 10^{-2}$. (Nearest Integer) (Given molar mass in $\text{g mol}^{-1}$: $H:1, C:12, O:16$)

The following reaction is known as:$Phenol \xrightarrow[H^{+}]{CHCl_3 / NaOH} \text{Salicylaldehyde}$

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The following reaction is known as:
$Phenol \xrightarrow[H^{+}]{CHCl_3 / NaOH} \text{Salicylaldehyde}$