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(A) The reaction is the acidic cleavage of a cyclic ether with $HI$. The ether oxygen gets protonated by $H^+$. The cleavage occurs at the bond that l

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(A) The reaction is the acidic cleavage of a cyclic ether with $HI$. The ether oxygen gets protonated by $H^+$. The cleavage occurs at the bond that leads to the formation of a more stable carbocation. In this case,the bond between the oxygen and the tertiary carbon atom breaks to form a stable benzylic-tertiary carbocation. The iodide ion $(I^-)$ then attacks this carbocation to form the final product. The structure of the product is $2-(2-iodo-propan-2-yl)phenol$ or a related derivative where the ring is opened,specifically forming an alcohol and an alkyl iodide. The correct product is the one where the $I$ is attached to the tertiary carbon and the $OH$ is attached to the primary carbon of the side chain.

The major product of the following reaction is

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