The major product of the following synthetic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction sequence is as follows:$1$. Chlorination of propane $(CH_3CH_2CH_3)$ with $Cl_2$ in the presence of light $(hv)$ gives $1$-chloroprop

Vedclass · Accepted Answer

$CH_2=CHCH_2OH$

Vedclass · Answer

(C) The reaction sequence is as follows:$1$. Chlorination of propane $(CH_3CH_2CH_3)$ with $Cl_2$ in the presence of light $(hv)$ gives $1$-chloropropane as the major product: $CH_3CH_2CH_3 + Cl_2 \xrightarrow{hv} CH_3CH_2CH_2Cl + HCl$.$2$. Dehydrohalogenation of $1$-chloropropane with alcoholic $KOH$ gives propene: $CH_3CH_2CH_2Cl \xrightarrow{	ext{alc. } KOH} CH_3CH=CH_2 + KCl + H_2O$.$3$. High-temperature chlorination of propene $(773 \ K)$ leads to allylic substitution,forming allyl chloride: $CH_3CH=CH_2 + Cl_2 \xrightarrow{773 \ K} ClCH_2CH=CH_2 + HCl$.$4$. Nucleophilic substitution of the allylic chloride with aqueous $AgOH$ (or $NaOH$) replaces the $Cl$ atom with an $OH$ group to form allyl alcohol: $ClCH_2CH=CH_2 + AgOH_{(aq)} \longrightarrow HOCH_2CH=CH_2 + AgCl$.

The major product of the following synthetic reactions is

Similar Questions

What is the product of $1, 4$-addition in the reaction shown below?

Compound $(X)$ will be:
Compound $(X) \xrightarrow[Pt]{5H_2} \text{Saturated compound}$
Compound $(X) \xrightarrow{AgNO_3} \text{Precipitate}$
Compound $(X) \xrightarrow[Me_2S]{O_3} OHC-CH_2-CH_2-CO-CHO + HOOC-CHO + HCOOH + OHC-CHO$

Give the isomers of $C_3H_6$ and their names.

Write chemical equations for the combustion reaction of the following hydrocarbons:
$(i)$ Butane $(ii)$ Pentene $(iii)$ Hexyne $(iv)$ Toluene

Arrange the stability of the given gem-diols in decreasing order:
$I$: Cyclopropane$-1,1-$diol
$II$: Cyclobutane$-1,1-$diol
$III$: Cyclopentane$-1,1-$diol

Vedclass Test Series

Exam Paper Generator

Online Exam Module