The mass density of a nucleus varies with mas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The radius of a nucleus is given by $R = R_0 A^{1/3}$,where $R_0$ is a constant.The volume of the nucleus is $V = \frac{4}{3} \pi R^3 = \frac{4}{3

Vedclass · Accepted Answer

constant

Vedclass · Answer

(C) The radius of a nucleus is given by $R = R_0 A^{1/3}$,where $R_0$ is a constant.The volume of the nucleus is $V = \frac{4}{3} \pi R^3 = \frac{4}{3} \pi (R_0 A^{1/3})^3 = \frac{4}{3} \pi R_0^3 A$.The mass of the nucleus is approximately $M = A 	imes m_p$,where $m_p$ is the mass of a nucleon.The mass density $ho$ is defined as $ho = \frac{M}{V} = \frac{A 	imes m_p}{\frac{4}{3} \pi R_0^3 A} = \frac{m_p}{\frac{4}{3} \pi R_0^3}$.Since $m_p$,$R_0$,and $\pi$ are constants,the mass density $ho$ is independent of the mass number $A$ and remains constant for all nuclei.

The mass density of a nucleus varies with mass number $A$ as

Similar Questions

The radius of the nucleus of silver (atomic number $Z = 47$) is $3.4 \times 10^{-14} \ m$. Calculate the electric potential on the surface of the nucleus. (Given: $e = 1.6 \times 10^{-19} \ C$,$\frac{1}{4\pi\epsilon_0} = 9 \times 10^9 \ N \ m^2/C^2$)

The surface areas of two nuclei are in the ratio $9: 25$. The mass numbers of the nuclei are in the ratio

Write the value of the $R_0$ constant used in the formula for the radius of a nucleus.

If the nuclear radius of ${}_{13}^{27}Al$ is $3.6 \, fm$,the approximate nuclear radius of ${}_{29}^{64}Cu$ in fermi is .......... $fm$.

The most stable particle in the Baryon group is

Vedclass Test Series

Exam Paper Generator

Online Exam Module