The mass of a photon with a wavelength equal | vedclass

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Question

(C) The de Broglie relation is given by $\lambda = \frac{h}{mv}$,where $m$ is the mass of the photon,$h$ is Planck's constant $(6.626 	imes 10^{-34}

Vedclass · Accepted Answer

$1.4285 	imes 10^{-32} \ kg$

Vedclass · Answer

(C) The de Broglie relation is given by $\lambda = \frac{h}{mv}$,where $m$ is the mass of the photon,$h$ is Planck's constant $(6.626 	imes 10^{-34} \ J \ s)$,and $v$ is the velocity of the photon.Rearranging for mass: $m = \frac{h}{v \lambda}$.The velocity of a photon $(v)$ is $3 	imes 10^{8} \ m \ s^{-1}$.The wavelength $(\lambda)$ is $1.54 	imes 10^{-8} \ cm = 1.54 	imes 10^{-10} \ m$.Substituting the values: $m = \frac{6.626 	imes 10^{-34} \ J \ s}{(3 	imes 10^{8} \ m \ s^{-1}) 	imes (1.54 	imes 10^{-10} \ m)}$.$m = \frac{6.626 	imes 10^{-34}}{4.62 	imes 10^{-2}} \ kg = 1.434 	imes 10^{-32} \ kg$.Rounding to the nearest provided option,the correct answer is $1.4285 	imes 10^{-32} \ kg$.

The mass of a photon with a wavelength equal to $1.54 \times 10^{-8} \ cm$ is

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