The mass of gas adsorbed,$x$,per unit mass of adsorbent,$m$,was measured at various pressures,$p$. $A$ graph between $\log(x/m)$ and $\log p$ gives a straight line with slope equal to $2$ and the intercept equal to $0.4771$. The value of $x/m$ at a pressure of $4 \text{ atm}$ is: (Given $\log 3 = 0.4771$)

In the adsorption of a gas on a solid,the Freundlich isotherm is obeyed. If the slope of the plot of $\log(\frac{x}{m})$ versus $\log(p)$ is zero,then the extent of adsorption is:

The given graphs $I$,$II$,$III$,and $IV$ represent general trends observed for different physisorption and chemisorption processes under mild conditions of temperature and pressure. Which of the following choice$(s)$ about $I$,$II$,$III$,and $IV$ is (are) correct?
$(A)$ $I$ is physisorption and $II$ is chemisorption
$(B)$ $I$ is physisorption and $III$ is chemisorption
$(C)$ $IV$ is chemisorption and $II$ is chemisorption
$(D)$ $IV$ is chemisorption and $III$ is chemisorption

During adsorption,the $\Delta H$ is negative and the magnitude of this negative value

The adsorption of a gas at the boiling point of the gas follows the isotherm shown in the figure. Identify the correct thermodynamic properties at point $C$.

Assertion : In chemisorption,adsorption first increases with temperature and then decreases.
Reason : Heat keeps on providing more and more activation energy.